I need help asap on a trig question!!
?
post your question please
find the exact values of the trig functions of the angle below. (Use the Pythagorean Theorem to find the third side)
There is a triangle with a hypotenuse of 41 and an adjacent of 9, the opposite is missing.
|dw:1443394526440:dw| something like this?
did I get the drawing right or...?
yes
ok, do you know how to find the length of the missing side?
yeah it's where you do a^2 + b^2 = c^2 and then you square root it
ok, so what's the missing side?
I got 42, but my pre calc book got 40, so I really don't know what I did wrong
9^2 + x^2 = 41^2
solve for x
ohh, okay. I got 40 as my answer. Thank you so much
yup, x = 40 so now we have all three sides, now comes the easy part|dw:1443395117726:dw|
so, our trig functions are: sin(theta) = opposite/hypotenuse cos(theta) = adjacent/hypotenuse tan(theta) = opposite/adjacent
csc(theta) = hypotenuse/opposite sec(theta) = hypotenuse/adjacent cot(theta) = adjacent/opposite
now all you need to do is look at the triangle and plug in the numbers where they belong
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