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Mathematics 9 Online
OpenStudy (anonymous):

the diameter of circle symbol z is 5 in. what is the area in terms of pi ?

OpenStudy (anonymous):

Nnesha (nnesha):

what's the formula to find AREA of a circle ??

OpenStudy (anonymous):

a=pi radius squared

Nnesha (nnesha):

yes right and diameter is half of radius you can use this formula to find radius \[\huge\rm r=\frac{ d }{ 2 }\]

OpenStudy (anonymous):

so 2.5 in squared ?

Nnesha (nnesha):

yes right take square of 2.5

OpenStudy (anonymous):

huh?

Nnesha (nnesha):

well radius is 2.5 right ?

OpenStudy (anonymous):

yes it is

Nnesha (nnesha):

\[\huge\rm A =\pi r^2\]

Nnesha (nnesha):

substitute r for 2.5 ^^

OpenStudy (anonymous):

ok i get 6.25

Nnesha (nnesha):

right

Nnesha (nnesha):

and we have to write it interms of pi

OpenStudy (anonymous):

ok so 6.25pi in squared

OpenStudy (anonymous):

can you help me with another one @Nnesha

Nnesha (nnesha):

i willlll try not sure:=)

OpenStudy (anonymous):

can you help @DanJS

OpenStudy (danjs):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

this is the question

OpenStudy (danjs):

the point C(x,y) is 3/4 the way from A to B along a line... youc an set up 2 equations involving x and y and solve or...

OpenStudy (danjs):

since it is a line with a constant slope , the x and y components of that form a right triangle realizing that the relation between the lengths of each side by the pythagorean theorem c^2 = a^2 + b^2 if you shrink the hypotenuse down by 3/4 you have to do that to the other terms too

OpenStudy (danjs):

(3/4)c^2 = (3/4)*a^2 + (3/4)*b^2

OpenStudy (anonymous):

ok

OpenStudy (danjs):

so you can just look and see the change in x coordinate, and find 3/4 that, and add that to the start value

OpenStudy (danjs):

Same for y coordinate

OpenStudy (anonymous):

ok so how do i this then ?

OpenStudy (danjs):

The length in the x direction from A to B is 16, 3/4 of that is 12 start at A and move 12 in the X direction, that is the x coordinate of C

OpenStudy (danjs):

do the same for the Y direction

OpenStudy (anonymous):

so 2,0

OpenStudy (anonymous):

thats what i got

OpenStudy (danjs):

yeah, sounds good

OpenStudy (danjs):

It is just basically shrinking a right triangle by 25% then seeing where it lies on the coordinates

OpenStudy (anonymous):

so i got that right ?

OpenStudy (danjs):

or you can do it by setting up 2 equations involving x and y in the point N, then solving for the x and y

OpenStudy (danjs):

Distance AC = 3/4 * Distance AB and equation of the line through AB

OpenStudy (anonymous):

ok cool but am i right ?

OpenStudy (danjs):

yes, you can check by just calculating the distances AB and AC and check if they are correct

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