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Slopes of secant lines.
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@zepdrix :)
Put each value of x into the function\[y=\frac{ 4 }{ 2-x }\]and calculate the corresponding y-value. Can you do that for the first one?
= -4.44444...
so the first Q point is = (2.9, -4.44..)
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Very good. So now you have the the coordinates of point Q on the secant line as (2.9, -4.444444). With point P given as (3, -4), can you calculate the slope of PQ?
4.4444444
Is that correct? :)
Recall that the slope calculation looks like\[m_{PQ} = \frac{ y_Q - y_P }{ x_Q - x_p }\]
Well done. That's correct. Now repeat these same calculations for each part of the question. Don't forget to keep six decimal places to satisfy the question.
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Thank you so much!!
You're welcome.
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