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expand 9y^2-(3/2)y+(1/16)
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do you mean factorize?
Whoops! Yes I meant factorize lol
because if so, then the simplest way I can think of, is to use the quadratic formula and let the equation above equal to zero so you can then solve for both values of y and put them in the form (y - (first value of y)(y - second value of y)
to clarify its (y - {first value of y})(y - {second value of y})
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