Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (anonymous):

Will give a fan and a medal for a direct answer to this question.

OpenStudy (anonymous):

http://picpaste.com/Capture_4-7lUenpUw.PNG

OpenStudy (anonymous):

@SwagHatKid

OpenStudy (anonymous):

(4w + 1) • (16w2 - 4w + 1) ————————————— 64

OpenStudy (anonymous):

16

OpenStudy (anonymous):

Oopsie

OpenStudy (anonymous):

lel

OpenStudy (whpalmer4):

\[w^{-3} = \frac{1}{64}\] by laws of exponents, \[a^{-b} = \frac{1}{a^b}\]so we can write that as \[\frac{1}{w^3} = \frac{1}{64}\] it should be clear that this means \[w^3=64\]What number \(w\) makes \(w^3=w*w*w=64\) a true statement?

OpenStudy (anonymous):

thats ez

OpenStudy (anonymous):

i know the answer

OpenStudy (anonymous):

are you looking for help or the answer?

OpenStudy (whpalmer4):

Good, keep it to yourself, the OP needs to work it out...

OpenStudy (anonymous):

i love your optimistic response

OpenStudy (anonymous):

;-;

OpenStudy (anonymous):

@SwagHatKid What is it

OpenStudy (whpalmer4):

@DredayAJO Let's try some possible values for \(w\): how about \(w = 2\)? \[2*2*2 = 8\]oops, that's too small how about \(w = 5\)? \[5*5*5 = 125\]oops, too big

OpenStudy (anonymous):

:) thanx m8

OpenStudy (whpalmer4):

@DredayAJO have you tried \(w = 3\) and \(w = 4\)?

OpenStudy (anonymous):

Can you help me with a direct answer or no?

OpenStudy (anonymous):

I'm not in the mood to be tutored right now

OpenStudy (whpalmer4):

@DredayAJO If you can't be bothered to try multiplying 3*3*3 and 4*4*4 and see if either of them give you the answer you need, you may just be stuck. The OpenStudy Code of Conduct says that we are to guide you to find the answer, not do it for you.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!