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OpenStudy (spring98):
Which is the more reasonable measurement of the distance between the tracks on a CD:
1.6 • 10^–3 mm or 1.6 • 10^3 mm? Justify your answer.
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OpenStudy (spring98):
@mathlover2014 can you plz help me? i will medal. :)
OpenStudy (welshfella):
the distance between them is too small to be seen so its going to be a lot less than 1 mm
OpenStudy (welshfella):
are you familiar with negative exponents?
OpenStudy (spring98):
so is it this 1.6 • 10^3
OpenStudy (welshfella):
No 10^3 = 1000 mm
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OpenStudy (welshfella):
10^-3 = 1/1000 or 0.001
OpenStudy (spring98):
1/1000right?
OpenStudy (welshfella):
No - its one of the 2 options in your questiion.
The numbers I gave were only examples.
OpenStudy (welshfella):
- to help you learn the difference between positive and negative exponents.
OpenStudy (spring98):
ya i know but the negative on will be to small so it will be 1.6 • 10^3 mm
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OpenStudy (spring98):
@welshfella am i right?
OpenStudy (welshfella):
NO 1.6 * 10^3 = 1,600 mm which is the same as 1.6 meters
OpenStudy (welshfella):
check my first post
OpenStudy (spring98):
so the answer will be 1.6 • 10^–3 mm
OpenStudy (welshfella):
yes
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OpenStudy (spring98):
why?
OpenStudy (welshfella):
well have a look at a CD . Can you see the distance between the tracks/
OpenStudy (spring98):
yes
OpenStudy (spring98):
@welshfella would it because the other one would be to big for the tracks of a CD?
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