Question

How to find x intercept for x^4-4x^2?

Answer 1

Set the y=0
So it would be \[0=x^4-4x^2\]
Distribute it
\[0=x^2(x^2-4)\]
=
\[0=x^2(x+2)(x-2)\]

Answer 2

so would x be -2, 2 and 0?

Answer 3

does the x^2 count

Answer 4

Yes it does.

Yep, you got it all correct.

Answer 5

oh and then what about 3x^2-x-2?

Answer 6

\[3x^2-x-2=(3x+2)(x-1)\]

Answer 7

oh!!!!!

Answer 8

wow thank you so much

Answer 9

No problem!
Good luck on the rest.

Answer 10

I appreciate it :)

Answer 11

yes thank you.