Question

A sandbag was thrown downward from a building. The function f(t) = -16t2 - 64t + 80 shows the height f(t), in feet, of the sandbag after t seconds:

Part A: Factor the function f(t) and use the factors to interpret the meaning of the x-intercept of the function. (4 points)

Part B: Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? (4 points)

Part C: Use your answer in part B to determine the axis of symmetry for f(x)? (2 points)

Answer 1

Please halp

Answer 2

given expression is f(t) where is f(x) or is it a typo ?

Answer 3

F(t) is F(x), just replace t with x if you want

Answer 4

alright let's factor the right side
i have few mints sorry

Answer 5

It's fine

Answer 6

\[\huge\rm f(t)= \color{ReD}{-16t^2-64t+80}\]
first take out the common factor

Answer 7

The common factor is 8

Answer 8

well we need GREATEST common factor

Answer 9

Oh, 16 then my mistake

Answer 10

yes right and bec leading coefficient is negative we can take out the negative 16

Answer 11

and sorry gtg :(

Answer 12

Alright that leaves us with \[f(t) = -4 + 5\]

Answer 13

Okay bye

Answer 14

aw didn't get the help :(

sorry

Answer 15

alright when we find the common denominator we should divide all terms by the common factor \[\large\rm \color{blue}{\frac{ -16t^2 }{ -16 }-\frac{ 64t }{ -16}+\frac{ 80 }{ -16} }\]\[\large \rm f(t)=-16(\color{blue}{t^2+4t-5})\]

now factor t^2+4t-5
there are more than 3 ways to factor o the quadratic equation
you can use AC method(easy)
find two number when you multiply them you should get product of AC (a=leading coefficient , c=constant term)
and when you add or subtract them you should get middle term(b)

Answer 16

remember t^2 is same as 1t^2 so in this question leading coefficient is 1