Question

CAN SOMEONE HELP ME?!?!
Use the Remainder Theorem to completely factor p(x) = x^3 + 7x^2 + 11x + 5

Answer 1

I don't get what to do..................................................................................................... :'(

Answer 2

-1 works as a root. \(x+1\) is a factor.

Answer 3

so...what do i do?

Answer 4

how am i supposed to find the factor?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!!??!

Answer 5

divide p(x) by (x+1)

Answer 6

so..... x+1/x^3 + 7x^2 + 11x + 5

Answer 7

@freckles

Answer 8

do i divide those?

Answer 9

thx for the help..... :'(

Answer 10

well you divide p(x) by (x+1)
not (x+1) by p(x)

just like you know 2 is a factor of 6 and you can find another factor of 6 by dividing 6 by 2