CAN SOMEONE HELP ME?!?!
Use the Remainder Theorem to completely factor p(x) = x^3 + 7x^2 + 11x + 5

Question

CAN SOMEONE HELP ME?!?!
Use the Remainder Theorem to completely factor p(x) = x^3 + 7x^2 + 11x + 5

faolan · Answer

I don't get what to do..................................................................................................... :'(

parthkohli · Answer

-1 works as a root. $x+1$ is a factor.

faolan · Answer

so...what do i do?

faolan · Answer

how am i supposed to find the factor?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!?!!??!

freckles · Answer

divide p(x) by (x+1)

faolan · Answer

so..... x+1/x^3 + 7x^2 + 11x + 5

faolan · Answer

@freckles

faolan · Answer

do i divide those?

faolan · Answer

thx for the help..... :'(

freckles · Answer

well you divide p(x) by (x+1)
not (x+1) by p(x)

just like you know 2 is a factor of 6 and you can find another factor of 6 by dividing 6 by 2