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OpenStudy (anonymous):
Can someone help me with the slope intercept method? My question is y = -3/4x + 2 and y = 1/3x - 1. Thanks!!!
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pooja195 (pooja195):
y=mx+b <---slope intercept form
what do you mean by method?
OpenStudy (anonymous):
So I understand Table of values and normal intercept methods. The one with 2 intercepts. Just not this one.
OpenStudy (anonymous):
Method = how to do it
pooja195 (pooja195):
So do you have to list the slope and y intercept ?
OpenStudy (anonymous):
I have to graph it. Sorry I didn't mention that.
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OpenStudy (anonymous):
first you plot b. I know that. But after that is what I don't get.
pooja195 (pooja195):
ah ok this shouldnt be to hard lets start with y=-3/4x+2
We always start at 2 on the y axis (the one that goes up and down)
|dw:1444000276733:dw|
pooja195 (pooja195):
|dw:1444000322298:dw|
pooja195 (pooja195):
Slope equals rise over run
OpenStudy (anonymous):
and that is -3/4 right?
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OpenStudy (anonymous):
so it would be -1,5?
OpenStudy (anonymous):
-1,4*
pooja195 (pooja195):
Yes but in this case we go down 3 because it is negative
OpenStudy (anonymous):
Ok. So it is -1, 4. That is all my teacher requires. The base and the next. So for the next one, it would be 0,3?
OpenStudy (anonymous):
Next question, not interval or whatever.
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pooja195 (pooja195):
|dw:1444000450412:dw|
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