Question

Assume that the box contains 10 balls: 1 red, 5 green, and 4 blue. Two balls are drawn at random, one after the other without replacement.
What is the probability that the first ball was blue, given that the second was red

Answer 1

I tried this problem but my answer keeps coming out to be greater than 1

Answer 2

hmmm a little tricky cx

Answer 3

Okay so think

Answer 4

theres 1 red 5 green and 4 blue and its asking whats the probability that the first ball was blue

Answer 5

Do you have choices? :)

Answer 6

wait is this the way the formula for the answer should look (4/10*1/9)/((5/10*1/9)+(4/10*1/9)+(4/10*1/9))

Answer 7

Okay solve it :) and see if its one of the choices for your question :-) if you have any

Answer 8

no its a blank we fill

Answer 9

Okay i see :) do you do k12?

Answer 10

k12?

Answer 11

Oh nvm its a homeschooling thing cx

Answer 12

I got the right answer :D

Answer 13

Anyways ima try it out :-)

Answer 14

You did? Well congrats :)

Answer 15

yeah

Answer 16

If you need help with anything else just ask cx even tho i did really get to help xD

Answer 17

Tag me into questions cx

Answer 18

okay thanks :)