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Given that f(x) = 2x + 1 and g(x) = the quantity of 3x-1/2 solve for g(f(3)). A. 5 B. 7 C. 9 D. 10
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clarification: \(g(x) = \frac{3x-1}{2}\) or is it \(g(x) = 3x-\frac{1}{2}\) ?
the first one
Ok :)
We can find what f(3) is first
f(x) = 2x + 1 \(\implies\) f(3) = 2(3) + 1
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@mariyakelly
okay I don't know how to solve that @Jhannybean
What is 2 * 3?
then add 1.
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