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OpenStudy (calculusxy):
\[\huge 12x^2 + 12x + 3\]
OpenStudy (calculusxy):
@Nnesha @hartnn
OpenStudy (rizags):
factor out a 3 first
OpenStudy (calculusxy):
\[\large 3(4x^2 + 4x + 1) \]
OpenStudy (rizags):
Then you'll notice something about the resulting quadratic
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OpenStudy (rizags):
hint: \[(a+b)^2 = a^2+2ab+b^2\]
OpenStudy (calculusxy):
i still don't understand
OpenStudy (rizags):
using my model, let\[\large a=2x\] and \[\large b=1\]
OpenStudy (calculusxy):
ok
OpenStudy (calculusxy):
can you please get to the point?
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OpenStudy (rizags):
ok, then \[12x^2+12x+3 = 3(2x+1)^2\]
Nnesha (nnesha):
there are like 4+ ways to factor quadratic equation
i like AC method
where we find two numbers when we multiply them we should get product of AC (a=leading coefficient , C= constant )
and when we add them we should get middle term which is b
\[\rm Ax^2+Bx+C\]
a=leading coefficient
b=middle term
c-constant
Nnesha (nnesha):
|dw:1444168815625:dw|
multiply A times C
what two numbers you should multiply to get 4 and when you add them you should get 4