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Mathematics
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OpenStudy (meilendurcer):
If m
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OpenStudy (meilendurcer):
OpenStudy (phantomcrow):
How did you arrive to that answer?
OpenStudy (phantomcrow):
Remember that if EB is perpendicular to BC, then angle EBC is 90 degrees.
OpenStudy (meilendurcer):
subtract 3y
OpenStudy (phantomcrow):
From what?
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OpenStudy (meilendurcer):
7y
OpenStudy (phantomcrow):
Hm. It says that angle EBF is 7y-3 and angle FBC is 3y +3.
OpenStudy (meilendurcer):
\[7y-3=3y+3\]
OpenStudy (phantomcrow):
These two angles make up angle EBC
OpenStudy (phantomcrow):
It isn't given that the two angles are congruent. If the value of the two angles were congruent, then this would work. But that info isnt given
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OpenStudy (meilendurcer):
i know there's another way to put them but i forgot my notes
OpenStudy (phantomcrow):
Its fine. You see that EBF AND FBC equal EBC, right?
OpenStudy (meilendurcer):
yes
OpenStudy (phantomcrow):
Alright. And since the question tells us that assuming EBC is perpendicular, what is the value of y. So EBC=90.
\[(7y-3)+(3y+3)=90\]
OpenStudy (meilendurcer):
yeah that's the one
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OpenStudy (phantomcrow):
Alright. So now use algebra to solve for y and see what you get.
OpenStudy (meilendurcer):
y=9?
OpenStudy (phantomcrow):
Yep.
OpenStudy (meilendurcer):
thanks
OpenStudy (phantomcrow):
np
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