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Geometry
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Line AB contains points A (−2, 6) and B (4, 5). The slope of line AB is 1. negative 1 over 6 2.1 over 6 3.6
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2.
like hell
The slope of a line is\[\frac{ y _{2} -y _{1}}{ x _{2}-x _{1} }\] So plug in your y values in the top and your x values in the bottom
\[\huge \frac{6-5}{4-(-2)}\] will ifnd it
remember \[slope = \frac{ y2 - y1 }{ x2 - x1 }\]
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i got 5-6 over 4-(-2) so what do i do next?
Subtract them 5-6=1 4-(-2)=4+2=6 So the slope is....
6?
Don't forget the top
oh.. 1 over 6?
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there you go
yay! thank you!!
Oh actually I mistyped that myself. Should be -1/6
Sorry about that
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