I need complete help.. Complete the identity. Cos(a -b)/cos a cos b A. 1 + cot a cot b B. Tan a tan b + cot b C. 1 + tan a tan b D. 1 + cot a tan b
try expanding the cos(a-b) part
How? I look at my textbook, but it isn't helping me understand more.
then separate the fraction after the expansion do some canceling and finally just a little rewriting
you don't know the difference identity for cosine?
No. My textbook never showed or told me.
It just gives me problems to do and then I take my test.
sin(x-y)=sin(x)cos(y)-sin(y)cos(x) sin(x+y)=sin(x)cos(y)+sin(y)cos(x) cos(x+y)=cos(x)cos(y)-sin(x)sin(y) cos(x-y)=cos(x)cos(y)+sin(x)sin(y) so you never seen these identities? that is odd
Correct. I am working hard to learn.. But I am confused.
@freckles
yes?
Can you help me a little better?
can you tell me if you applied that identity yet?
Like, I am confused. I have done some sins, cos, and tans but not like this.
do you see the cos(a-b) on top?
do any of the identities I mentioned look like this on the left hand side?
I do and yes.
well can you apply that identity then...
like can you expand cos(a-b)
The expanding is the confusing part. Never done it.
so you don't see how cos(x-y) looks exactly like cos(a-b) except in the place of x we have a and in the place of y we have b?
I see now.
replace the x and y on the right hand side with a and b respectively
and you have expanded cos(a-b)
Okay. Is that all I do?
to expand cos(a-b) yes for the question you have asked here at the top, no
I actually gave a few more steps above after the expansion
Okay. Thanks!
something about separating the fraction canceling stuff and rewriting a bit
can you show me what you have after rewriting \[\frac{\cos(a-b)}{\cos(a)\cos(b)}\]
or show me what you have for the numerator please
Yes
Cos(x-y)= cos(x) cos (y) I am still somewhat confused
ok well it looks like you didn't use the identity I mentioned above
cos(x-y)=cos(x)cos(y)+sin(x)sin(y)
cos(a-b)=?
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Uhhh, ??? Sorry.. I have no clue. I have never done a problem like this. Cos(x-y)
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