Mathematics
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OpenStudy (anonymous):
4x + 1 over 3y2
What is the value of the expression above when x = 2 and y = 3? You must show all work and calculations to receive full credit.
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OpenStudy (michele_laino):
substituting your numerical data into your expression, we get:
\[4x + \frac{1}{3}{y^2} = 4 \cdot 2 + \frac{1}{3} \cdot {3^2} = ...\]
OpenStudy (michele_laino):
here, we have to compute the power, first
OpenStudy (anonymous):
can u sum it down a little im smart just not that smart
OpenStudy (michele_laino):
ok! next step is:
\[4x + \frac{1}{3}{y^2} = 4 \cdot 2 + \frac{1}{3} \cdot {3^2} = \left( {4 \cdot 2} \right) + \left( {\frac{1}{3} \cdot 9} \right) = ...?\]
OpenStudy (anonymous):
um what do i have to do
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OpenStudy (michele_laino):
you have to do multiplications first
OpenStudy (anonymous):
ok wht is the factors i use to multiply
OpenStudy (michele_laino):
first step:
\(4 \cdot 2=...\)
OpenStudy (anonymous):
8
OpenStudy (michele_laino):
ok! then:
\[{\frac{1}{3} \cdot 9}=...?\]
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OpenStudy (anonymous):
um 1 x 9 is 9 3 x 9 is 27
OpenStudy (michele_laino):
|dw:1444233369417:dw|
OpenStudy (anonymous):
so 3 x 1
OpenStudy (michele_laino):
yes!
OpenStudy (michele_laino):
what is \(3 \cdot 1=...?\)
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OpenStudy (anonymous):
3
OpenStudy (michele_laino):
finally, what is:
\(8 + 3=...?\)
OpenStudy (anonymous):
11
OpenStudy (michele_laino):
correct! That is your answer!
OpenStudy (anonymous):
11
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OpenStudy (michele_laino):
yes!
OpenStudy (anonymous):
thx ur awesome
OpenStudy (anonymous):
thx ur awesome
OpenStudy (michele_laino):
thanks! :)