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Geometry 19 Online
OpenStudy (anonymous):

How do you find the equation of a tangent line and also normal line when given an equation of the circle and a point that is NOT on the circle .. the problem x^2+y^2=13 and point (-4, 7) "find the equation of a tangent line and also normal line when given an equation of the circle and a point that is NOT on the circle"

OpenStudy (mrnood):

|dw:1444258760551:dw| The line that is normal is always a diameter, and passes through the centre. From the equation of th ecircle you know the cntre is (0,0) so you have 2 points on the normal line so can work out its equation. The slope of the tangent is perpendicular to the normal so its slope is -1/m

OpenStudy (mrnood):

because the point is inside the circle there is no tangent through the point...

OpenStudy (anonymous):

no the point is outside the circle ...this is how it look..

OpenStudy (anonymous):

1 sec

OpenStudy (mrnood):

ok - sorry - i see my mistake:

OpenStudy (mrnood):

|dw:1444259449121:dw|

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