Question

(4,1); perpendicular to y=1/3x+3. How to solve it?

Answer 1

@Jadedry

Answer 2

@Hero @ganeshie8

Answer 3

@ParthKohli @mathstudent55

Answer 4

What exactly are you trying to solve here ?

Answer 5

I want to know the method to solve the problem

Answer 6

I need to use like y-y1=m(x-x1)

Answer 7

to find the equation

Answer 8

that's fine,
may i know what equation you're trying to find ?

Answer 9

the problem is not clear to me yet..

Answer 10

@Epicteatime

Hi again!

I too am a bit confused as to what you are trying to find. :c

Answer 11

the equation for the line that passes through the given point and satisfies the given condition. And Hi jade :3

Answer 12

Like, do I use the opposite slope? -3/1 since its perpendicular?

Answer 13

So the line has to be perpendicular to y = 1 and it has to pass through the point 4,1 ?

Answer 14

yes, basically

Answer 15

you have an X and the Y just plug in the numbers and then get the answer of Y = 1/15

Answer 16

Then the equation for the line should be x = 4

It would be perpendicular to you, which is a horizontal line, and it would pass through 4,1

Answer 17

Unless there is another piece of info I should take into account?

Answer 18

hmmm

Answer 19

like if it was parallel, I could have used the slope from the line stuff that is given.

Answer 20

Wait, Is the equation for Y

\[y = \frac{ 1 }{ 3x+3 }\] ?

Answer 21

uhh, I have no idea xD Thats why I'm here xD

Answer 22

Your textbook should tell you though, the format in which you wrote it was a bit confusing, I thought y=1 at first?

Answer 23

hmm, maybe maybe xD

Answer 24

its ok, i'll ask my teacher/ look at my textbooks :3 gnat :D

Answer 25

*gnyt

Answer 26

Ah, okay. Good night! c:

Answer 27

Y does equal 1 it says so in the point for the graph( 4,1)

Answer 28

yep, completely :D