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Having a blank moment.. please help me write square root of u on the top line
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\[\frac{ 2u-1 }{ \sqrt{u} }\]
does it become (2u-1)(u)^(-0.5)
Do you want o solve for u?
i want to bring square root of u to the top
\[\frac{ 2u-1 }{ \sqrt{u} }=2u-2*x ^{\frac{ -1 }{ 2 }}\]
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is that correct?
i mean 2u-1
\[\frac{ (2u-1^{(0.05u)} }{ 1 }\]
omg i cant do that....because its a relationship at the top!!!!!! opps
(2u−1(0.05u)1
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\[\frac{ 2u-1 }{ \sqrt{u} }=\frac{ 2u }{ \sqrt{u} }-\frac{ 1 }{ \sqrt{u} }\]
If you multiply \(\rm \sqrt u\) by \(\rm \sqrt u\) will get rid of the square root down there :) ya?
\[\large\rm \frac{(2u-1)}{\sqrt{u}}\cdot\color{royalblue}{\frac{\sqrt u}{\sqrt u}}\]Gotta do this fancy business
this is ok because your effectively multiplying by 1
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