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Mathematics 14 Online
OpenStudy (anonymous):

pi is polynomial?

OpenStudy (owlet):

no, it is irrational. polynomials contain variables that have different exponents on them

OpenStudy (freckles):

constants are still polynomials

OpenStudy (freckles):

\[a_n x^{n}+a_{n-1}x^{n-1}+ \cdots a_2 x^2+a_1 x_1+a_0 \text{ is a polynomial } \\ \text{ where } n \text{ is a positive integer } \\ \text{ and } a_i \text{ is a real number }\]

OpenStudy (freckles):

And I guess you could define polynomials with complex coefficients instead

OpenStudy (freckles):

And above I mean to say all the exponents are either positive integers or zero

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Pi is not a polymonial. It is an irrational number.

OpenStudy (anonymous):

Like freckles said.

OpenStudy (freckles):

no I was saying pi a polynomial

OpenStudy (freckles):

constants are polynomials

OpenStudy (freckles):

pi is a constant

OpenStudy (freckles):

pi is a irrational number I agree with that but pi is also a polynomial

OpenStudy (anonymous):

Oh.

OpenStudy (anonymous):

But aren't polymonials equations, usually?

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