Question

What is the solution set of the equation
2y^2 - 3y = 2
The solution set is {-1/2, [1]}

Answer 1

this is a quadratic equation
you can subtract 2 on both sides and put it in the form:
ay^2+by+c=0

Answer 2

I'm still very confused. Would you be able to tell me exactly how to do it?

Answer 3

Are you asking me how to subtract 2 on both sides?

Answer 4

2y^2-3y-2=2-2
2y^2-3y-2=0

Answer 5

now you can try to factor
or use quadratic formula