I'm confused with simplifying expressions with brackets and parantheses... Can someone give me step by step help with this problem?
let's deal with the bracket first whenever u see negative sign outside the paretheses first you should use distributive property \[[(6x ^{2}+3x+2)\color{ReD}{-(3x ^{2}-4x+5)}]-(x ^{2}+4x-5)\] distribute parentheses by negative one
\[[(6x ^{2}+3x+2)-(-3x ^{2}-4x+5)]-(x ^{2}+4x-5)\]
let's deal with the bracket first whenever u see negative sign outside the paretheses first you should use distributive property \[[(6x ^{2}+3x+2)\color{ReD}{-(-3x ^{2}-4x+5)}]-(x ^{2}+4x-5)\] distribute parentheses by negative one
so after distribution my equation looks like \[[6x ^{2}+3x+2+3x ^{2}+4x-5]-(x ^{2}+4x-5)\]
right now combine like terms in the bracket and then distribute parentheses by negative one :=)
so the answer I got was \[8x ^{2}+3x+8\]
\[[\color{ReD}{6x ^{2}+3x+2+3x ^{2}+4x-5}]-(x ^{2}+4x-5)\] what are like terms in the bracket ?
\[6x ^{2} + 3x ^{2} =9x ^{2}, 3x + 4x =7x , 2+ (-5) =3\]
hmme 2 +(-5 ) isn't positive 3 remember if the bigger number is negative then answer would be negative :=)
so it's -3. is that where I went wrong in my answer?
yes ::=)
ohhhh so I'm just bad at adding negatives and positives in my head. lol Thank you so much!!!!
np :=)
good work btw :=)
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