Question

Help! Please!

-8-4-(-2)-(+2)(-3)

Answer 1

first you must put any 'minus' signs inside the brackets they refer to.

Rewrite the sum with the brackets evaluated...

Answer 2

(btw - have you missed out a + or - between the last 2 brackets?)

Answer 3

This is order of operations

Answer 4

and first is B for brackets

so do what I suggested first

Answer 5

@MrNood Im stuck

Answer 6

It can either be PEDMAS or BEDMAS P = Parentheses B = Bracket

Answer 7

Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

Answer 8

Okay but i keep getting -16 & in my book it has a different answer

Answer 9

-8-4-(-2)-(+2)(-3) so using the rules we see that ((+2)(-3) would come first

Answer 10

Yes and that would be -6 right

Answer 11

so then you have -8-4-(-2)-(-6)

Answer 12

right now do the multiplication of -1*(-2) and -1*(-6)

Answer 13

so that should give you -8-4+2+6

Answer 14

from there you can just do -8-4 = -12 and 2+6 = 8 and add the results together

Answer 15

Okay i think i got it from there

Answer 16

This is an "order of operations" problem.
In this case, the parentheses are here for only two reasons:
1) to separate a negative sign from an addition sign
2) to show a product

Using PEMDAS, you can skip PE, and go right to
MDAS which means the following:
MD - multiplications and divisions in the order they appear from left to right
AS - additions and subtractions in the order they appear from left to right

\(-8-4-(-2)-(+2)(-3)\)

Answer 17

\(-8-4-(-2)-\color{red}{(+2)(-3)}\)

The operation shown in read above is a multiplication, so it has to be done first.

\(= -8-4-(-2)-\color{red}{(-6)}\)

Now all you have left is subtractions, so do them in order from left to right, one at a time.

\(= -8-4-(-2)-(-6)\)

\(= -12-(-2)-(-6)\)

\(= -10-(-6)\)

\(= -4\)