Can Someone see if I did this right?

The functions q and r are defined as follows.
q(x)=-x+1
r(x)=-2x^2-1
Find the value of
r(q(2)

r(x)=-2(2)^2-1 is r=-9

replace the -9 in the other equation

q(-9)=-9+1 which gave me 0.88889

Question

Can Someone see if I did this right?

The functions q and r are defined as follows.
q(x)=-x+1
r(x)=-2x^2-1
Find the value of 
r(q(2)

r(x)=-2(2)^2-1 is r=-9

replace the -9 in the other equation

q(-9)=-9+1 which gave me 0.88889

flvskidd · Answer

I'm doing the same thing in math right now hold up.

teller · Answer

Alright...

flvskidd · Answer

Okay so the q goes in the middle. It would be 1(2x^2-1)

flvskidd · Answer

This is inverse functions right? I haven't started with exponents yet in the functions.

teller · Answer

No it's  Composition of two Functions

flvskidd · Answer

Oh I might have an answer sorry.

flvskidd · Answer

So yeah as far as I know all you have to do is put the one on the outside of 2x^2-1 and do the distributive property.

flvskidd · Answer

Here is an example from my H.W.

flvskidd · Answer

Maybe this will help you.