Question

Can someone help me out on finding the amplitude, period, phase shift on sin cos graphs ?

Answer 1

y=sin(pi-x) i dont now what the period or phase shift is for this equation.

Answer 2

This may help.

Answer 3

is the period 2?

Answer 4

`y=sin(pi-x)` is the same as `y=1*sin(-1x-(-pi))+0`

notice how
A = 1
B = -1
C = -pi
D = 0

Answer 5

yes

Answer 6

so you just switched the pi-x around?

Answer 7

yes I wrote it as -x+pi

then change that to -x - (-pi)

Answer 8

period= -2pi?

Answer 9

more like

T = 2pi/|B|
T = 2pi/|-1|
T = 2pi/1
T = 2pi

The period must be positive

Answer 10

could you teach me how to find the amplitude and period of a given cos or sin graph?

Answer 11

what is the value of A in this case?

Answer 12

1

Answer 13

b=-1

Answer 14

c=pi

Answer 15

A = 1

|A| = |1| = 1 is the amplitude

Answer 16

phase shift=pi

Answer 17

C = -pi

C/B = -pi/(-1) = pi is the phase shift

Answer 18

D = 0, so y = 0 is the midline

Answer 19

on my quiz yesterday one of the problems was like...... y=2+3cos(2x-4)......is there a vertical shift in that??

Answer 20

y=2+3cos(2x-4) is the same as y=3cos(2x-4)+2

D = 2 is the last term tacked on
y = 2 is the midline (shifted 2 units up from y = 0)

Answer 21

ohhh

Answer 22

i also had problems on parts where it showed just the graph and no equation, and i had to identify the amplitude, period then the actual equation. can you help me with that. like draw a graph and ask me to identify the period amplitude and equation?

Answer 23

the amplitude is half the vertical distance from the highest point to the lowest point

the period is the horizontal distance from one peak to the next neighboring peak

Answer 24

wavelength is the same as period

http://38.media.tumblr.com/72ab98490685290d67c72d72a859cd93/tumblr_inline_nivaaaEDSf1qi84oh.png

Answer 25

hmmmm.

Answer 26

im still having problems

Answer 27

ok post your image