PLEASE HELP!!!!!
A quadratic equation is shown below:
9x2 − 16x + 60 = 0
Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)
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Directrix (directrix):
I assume that we have to get the discriminant first.
Directrix (directrix):
ax^2 + bx + c + 0
9x2 − 16x + 60 = 0
a = 9
b = -16
c = 60
Directrix (directrix):
@Juliamariah
For this problem, what is the value of b^2 - 4*a*c
OpenStudy (anonymous):
@Directrix
-2416
Directrix (directrix):
When you squared the -16, did you get a positive number?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
i got -256
Directrix (directrix):
b^2 - 4*a*c
(-16)^2 - 4 * (9 ) * (60) =
256 - ?
OpenStudy (anonymous):
-1904
Directrix (directrix):
Correct.
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Directrix (directrix):
Click on the attachment in the second post I made in this thread and see how the roots are described.
Directrix (directrix):
Nature of the roots
Click on attachment here vvvvv
Directrix (directrix):
Do you see that the roots are not real.
OpenStudy (anonymous):
Yes
Directrix (directrix):
Did you post part b ? @Juliamariah
Or, do you have a question about part A?
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