Ask your own question, for FREE!
Algebra 22 Online
OpenStudy (anonymous):

Please Help

OpenStudy (anonymous):

OpenStudy (anonymous):

@LynFran

OpenStudy (babynini):

Hey :) you want to get a common denominator. Which 2 options have that?

OpenStudy (anonymous):

A and B

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

or no?

OpenStudy (babynini):

Perfect! So to get a common denominator you have to multiply it, right? So you must do the same to tbe top.

OpenStudy (anonymous):

so its B then right?

OpenStudy (babynini):

Not quite

OpenStudy (anonymous):

or no?

OpenStudy (babynini):

Sorry, doing this on my phone so it is taking longer xD

OpenStudy (babynini):

Not b

OpenStudy (babynini):

Which means it must be..

OpenStudy (anonymous):

so it must be A then but im still not sure why tho

OpenStudy (anonymous):

im still confused

OpenStudy (babynini):

Ok:) let me try and write it out. So the denominators are 7 and (x+5) and you got the common demoninator 7(x+5) So you have to multilly the top also. Which looks like: ((×+4)(×+5))/7(×+5) - ((7)(×+3))/7(×+5)

OpenStudy (anonymous):

\[\frac{ x+4 }{ 7 }-\frac{ x+3 }{ x+5 }\]\[\frac{ (x+4)(x+5) }{ 7(x+5) }-\frac{ 7(x+3) }{ 7(x+5) }\]\[\frac{ (x ^{2}+9x+20)-(7x+21) }{ 7(x+5) }\]

OpenStudy (babynini):

Thanks ari:)

OpenStudy (anonymous):

your welcome ma'am

OpenStudy (anonymous):

oh now i see what you where talking about

OpenStudy (anonymous):

thank you @ArifL and @@Babynini

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!