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Using the completing-the-square method, find the vertex of the function f(x) = 2x2 − 8x + 6 and indicate whether it is a minimum or a maximum and at what point.
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first divide through by 2 = 2( x^2 - 4x + 3) can you continue ?
kinda
complete the square on what is in the parenthese = 2( x - 2)^2 - A + 3) can you work out what A is?
a is 1?
the -2 came from dividing the -4 in 4x by 2 Now you have to correct for the last term in the expansion of (x - 2)^2
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(x - 2)^2 = x^2 - 4x + what?
no, not 1
(x - 2)(x - 2) = x^2 - 2x - 2x -2 * -2
sorry guy gotta go right now - the last term is -2*-2 = +4 so A = 4
oh thats right
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Maximum at (2, −2) Minimum at (2, −2) Maximum at (2, 6) Minimum at (2, 6) but which one is right?
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