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OpenStudy (anonymous):
ALGEBRA HELP PLEASEEE
Find the GCF of the terms of each polynomial. Then factor the polynomial.
22. 12p^4 + 16p^3 + 8p =
24. 45c^5 - 63c^3 + 27c =
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OpenStudy (anonymous):
im guessing its taking out the common terms then simplifying
OpenStudy (jdoe0001):
\(12p^4 + 16p^3 + 8p\qquad
\begin{cases}
12=3\cdot 2\cdot 2\\
16=2\cdot 2\cdot 2\cdot 2\\
8=2\cdot 2\cdot 2\\
p^4=pppp\\
p^3=ppp
\end{cases}\impliedby hint\)
OpenStudy (jdoe0001):
\(45c^5 - 63c^3 + 27c \qquad
\begin{cases}
45=3\cdot 3\cdot 5\\
63=7\cdot 3\cdot 3\\
27=3\cdot 3\cdot 3\\
c^5=ccccc\\
c^3=ccc
\end{cases}\impliedby hint\)
OpenStudy (anonymous):
4p • (3p^3 + 4p^2 + 2) is this correct?
OpenStudy (anonymous):
@Vocaloid
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
`4p • (3p^3 + 4p^2 + 2) is this correct?`
yep, 12p^4 + 16p^3 + 8p = 4p(3p^3 + 4p^2 + 2)
OpenStudy (anonymous):
@jim_thompson5910 Okay and 4p • (3p^3 + 4p^2 + 2) is in standard form?
jimthompson5910 (jim_thompson5910):
it's in factored form
OpenStudy (anonymous):
Sorry, that's what I meant. Thank you
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jimthompson5910 (jim_thompson5910):
no problem
OpenStudy (anonymous):
Can you help me with a few more please?
jimthompson5910 (jim_thompson5910):
sure
OpenStudy (anonymous):
For #24 for factored form I got this: 9c • (5c^4- 7c^2 + 3)
jimthompson5910 (jim_thompson5910):
correct
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OpenStudy (anonymous):
Okay, thank you.
Simplify each product. Write in standard form.
38. (y - 6) (3y + 7) =
40. (4b - 3) (4b + 3) =
jimthompson5910 (jim_thompson5910):
for those, I would use the box method
|dw:1444872350866:dw|
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