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b-2/2=10/6 7/6=r-3/5
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@Outh-1
\[b-2/2=10-6\]
Is that what you are asking for?
solving proportions
2/2 simplifies to 1, and 10/6 simplifies to 5/3. That gives you b-1=5/3. You then find the least common multiple of 1 and 5/3, and that is three. You set the denominators both to 3, so b-3/3=5/3, and then you solve it from there.
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Same with the other problem, find the least common multiple, then solve for r.
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