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Geometry 20 Online
OpenStudy (anonymous):

What is the length of the red vertical angle?

OpenStudy (anonymous):

I chose 6 as my answer. Please explain why I may or may not be wrong :)

OpenStudy (welshfella):

we have a right angled triangle as below. Use the pythagoras theorem 5^2 = 4^2 + x^2 - find x |dw:1444907824835:dw|

OpenStudy (welshfella):

x is not = 6 subtracting 6^2 from bth sides of the equation:- x^2 = 5^2 - 4^2 x^2 = 25 - 16 find x

OpenStudy (welshfella):

* that is 4^2 not 6^2 (in the second line)

OpenStudy (anonymous):

25-16 = 9, so would x be 3^2?

OpenStudy (welshfella):

NO x^2 = 9 not x

OpenStudy (welshfella):

(3^2 = 9 , of course)

OpenStudy (welshfella):

so if x^2 = 9 , x = ?

OpenStudy (anonymous):

Lol........3?

OpenStudy (welshfella):

yes!

OpenStudy (welshfella):

3 * 3 = 9 the square root of 9 is 3

OpenStudy (welshfella):

the square root of 3^2 is 3!!

OpenStudy (welshfella):

OK? Any questions?

OpenStudy (anonymous):

Thank you.

OpenStudy (welshfella):

The longest side in a right angled triangle is the hypotenuse (sloping side) so that length of x can't be 6.

OpenStudy (welshfella):

yw

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