Question

What is the equation of the line that passes through (5, -2) and (-3, 4)?
3x - 4y - 7 = 0
3x + 4y - 7 = 0
-3x + 4y - 7 = 0

Answer 1

help plzzz

Answer 2

um let me think ok

Answer 3

ok

Answer 4

@welshfella @Compassionate

Answer 5

y = 7/4-(3 x)/4

Answer 6

x-intercept | 7/3~~2.33333
y-intercept | 7/4 = 1.75
slope | -3/4 = -0.75

Answer 7

@taivane easiest way to do this is to find the slope of those two points.

Answer 8

The idea is that if you find the slope, it would be clear that the line will pass through those two points.

\[y = m(x)+b \]

\[m = \frac{ y_{2}-y_{1} }{ x_{2}-x_{1} }\]

\[\frac{ -2-(4)}{ 5-(-3) } = \frac{ -6 }{ 8 } = \frac{ -3 }{ 4 } = slope,m \]

Answer 9

\[y - y _{1} = m(x - x_{1})\]

Points are (5, -2) and (-3, 4)