Question

The slope-intercept form of the equation of a line that passes through point (–3, 8) is y = -2/3x + 6. What is the point-slope form of the equation for this line?

y – 3 = –2/3(x + 8)

y + 3 = –2/3(x – 8)

y + 8 = –2/3(x – 3)

y – 8 = –2/3(x + 3)

Answer 1

point slope form : y - y1 = m(x - x1)

y = - 2/3x + 6...slope(m) is -2/3
(-3,8)...x1 = -3 and y1 = 8

now we sub
y - 8 = -2/3(x - (-3) =
y - 8 = -2/3(x + 3)

Answer 2

so its d

Answer 3

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line?


2x – 5y = –15

2x – 5y = –17

2x + 5y = –15

2x + 5y = –17