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A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and twenty-one more quarters than dimes. How many coins of each did she return?
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first let's take the value of each. nickels are worth 5 cents, dimes are worth 10 and quarters are worth 25. nickels = n dimes = d quarters = q
5n + 10d + 25q = 1,000 because we are dealing with cents. 1,000 cents is 10 dollars
it says that 9 more dimes than nickels were returned so d=n+9
5n + 10(n+9) + 25q = 1000
then it says 21 more quarters than dimes so q=21+d and we know that d=n+9, therefore q=n+9+21
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5n + 10(n+9) + 25(n+9+21) = 1,000
solve for n
remember that n = nickels, after you solve for n plug in and solve for the rest
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