Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (leahhhmorgannn):

http://prntscr.com/8s4jzp Elba writes the following proof for the theorem: If the diagonals of a quadrilateral bisect each other, the quadrilateral is a parallelogram:

OpenStudy (leahhhmorgannn):

Elba's proof 1. For triangles AOB and COD, angle 1 is equal to angle 2 as they are vertical angles. 2. AO = OC and BO = OD because it is given that diagonals bisect each other. 3. Therefore, the triangles AOB and COD are congruent by SAS postulate. 4. Similarly, triangles AOD and COB are congruent. 5. By CPCTC, angle ABD is equal to angle CDB and angle ADB is equal to angle CBD. 6. As the _______________ are congruent, the opposite sides of quadrilateral ABCD are parallel. 7. Therefore, ABCD is a parallelogram. Which is the missing phrase in Elba's proof? alternate interior angles corresponding angles corresponding sides opposite sides I put C, but I'm honestly clueless so @JackofallTradez

jimthompson5910 (jim_thompson5910):

|dw:1445035779314:dw|

jimthompson5910 (jim_thompson5910):

`5. By CPCTC, angle ABD is equal to angle CDB and angle ADB is equal to angle CBD. ` let's break this statement up ` angle ABD is equal to angle CDB` this means |dw:1445035916926:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!