Help please? Write the standard form of a line that contains a slope of 2/3 and passes through the point (1,1).
actually, lets make it even easier. standard form is simply mx + y = b
That's what's confusing me. How am I supposed to use the points here?
points are of the form (x,y), we can simply sub in the equation.
we are given m = 2/3. so our equation now is: (2/3)x + y = b.
why dont you try subbing in x = 1, and y = 1 into the equation and solve for b? that will be your solution.
So you simply just plug in those two points for x and y turning the equation into y=2/3x+1?
no sorry, try subbing into the equation we found above: -(2/3)x + y = b. (forgot to include the - last time! sorry) try finding b.
So instead -(2/3)1+1=b , would you then multiply -(2/3) into 1 making it positive and turning the equation into 2/3+1=b?
not quite. remember a negative (-2/3 in this case) and positive (1) = negative, so we would get back -2/3. simply sub in (x = 1 and y = 1) -(2/3)1+1=b -2/3 + 1 = b so what is b?
Is it one?
what is (-2/3) + 1, try it on your calculator. it is not 1.
It's 1/3
Yup.
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