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Integrate 1/(x(4-x^2)^(1/2)). I figured this was a case of trig substitution, but I couldn't get anywhere with it. I'm not sure where to go from here.
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The first thing that jumps out at me is the `(4-x^2)^(1/2)` which is really \(\Large \sqrt{4-x^2}\) Let's draw a right triangle with \(\Large \sqrt{4-x^2}\) as one of the legs |dw:1445051535641:dw|
are you able to determine the other missing sides?
2 and -x, right?
2 is the hypotenuse, x is the other leg |dw:1445051971280:dw|
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