Integrate 1/(x(4-x^2)^(1/2)). I figured this was a case of trig substitution, but I couldn't get anywhere with it. I'm not sure where to go from here.

Question

jim_thompson5910 · Answer

The first thing that jumps out at me is the `(4-x^2)^(1/2)` which is really $\Large \sqrt{4-x^2}$

Let's draw a right triangle with $\Large \sqrt{4-x^2}$ as one of the legs

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jim_thompson5910 · Answer

are you able to determine the other missing sides?

anonymous · Answer

2 and -x, right?

jim_thompson5910 · Answer

2 is the hypotenuse, x is the other leg

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