Question

Solve the following system.

y = (1/2)x^2 + 2x - 1 and 3x - y = 1

The solutions are ( ) and ( ) (remember to include the commas)

Answer 1

i would solve the second one for y = , then just set them equal y = y

Answer 2

solve for the x value(s) and then use those x's to get the corresponding y value(s)

Answer 3

y = (1/2)x^2 + 2x - 1 and y = 3x - 1

solve,
3x - 1 = (1/2)x^2 + 2x - 1

Answer 4

which when you combine like terms will give you 1/2x^2-x = 0

Answer 5

I got x=2

Answer 6

then you can just factor it using the quadratic formula.

Yes you should get X = 2 and X = 0