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Solve the following system. y = (1/2)x^2 + 2x - 1 and 3x - y = 1 The solutions are ( ) and ( ) (remember to include the commas)
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i would solve the second one for y = , then just set them equal y = y
solve for the x value(s) and then use those x's to get the corresponding y value(s)
y = (1/2)x^2 + 2x - 1 and y = 3x - 1 solve, 3x - 1 = (1/2)x^2 + 2x - 1
which when you combine like terms will give you 1/2x^2-x = 0
I got x=2
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then you can just factor it using the quadratic formula. Yes you should get X = 2 and X = 0
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