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Mathematics 20 Online
OpenStudy (babynini):

Find equation of tangent line and normal line?

OpenStudy (babynini):

Value of y' at 0.01 is = 1/25, I think.

OpenStudy (babynini):

@Miracrown

OpenStudy (bahrom7893):

\[y-y_1=M(x-x_1)\]Where M is the slope of the tangent line

OpenStudy (danjs):

Did you get the function for y' ?

OpenStudy (babynini):

Yes, well, I got the derivative of the first y equation thing.

OpenStudy (danjs):

what di dyou get?

OpenStudy (babynini):

\[y'(x)=\frac{ \frac{ x+9 }{ 2\sqrt{x} }-\sqrt{x} }{ (x+9)^2 }\]

OpenStudy (danjs):

\[y ' = \frac{ -(x-9) }{ 2\sqrt{x}*(x+9)^2 }\]

OpenStudy (babynini):

equivalent, yeah? maybe yours is easier to work with xD

OpenStudy (danjs):

i just put it in my calculator, lol sorry

OpenStudy (danjs):

quotient rule, bottom times derivative top minus top times derivative bottom, all over bottom squared

OpenStudy (babynini):

Why do we need to do the quotient rule if we already have the derivative?

OpenStudy (babynini):

ooh right, I see what you're saying. Yep, that's what I did haha

OpenStudy (danjs):

ok, the point given on the function is (x,y) = (1 , 0.1) use that in the derivative, and y' will tell you the slope of the tangent line there at the point

OpenStudy (babynini):

like plug x into the derivative?

OpenStudy (danjs):

yeah figure out f ' (x) =

OpenStudy (babynini):

k, well I think f(1) = 1/25

OpenStudy (danjs):

yes, the value of the derivative at any point is the slope of a tangent line to the function at tha tpoint, so the tangent line has slope 1/25, and goes through the given point (x,y) make a line equation from that

OpenStudy (danjs):

the normal is perpendicular to a tangent at some point, just use the perpendicular slope to 1/25 and the same point for the normal line

OpenStudy (babynini):

hmm is it y = 1/25x-0.14?

OpenStudy (danjs):

tangent line : y - y1 = f '(x) *(x - x1) normal line, same, cept slope is -1/f'(x)

OpenStudy (babynini):

or y= 0.04x-0.14 for the tangent line

OpenStudy (babynini):

so the normal would be.. y=-25x-0.14? o.o

OpenStudy (danjs):

just miscalculated i think ... y - 0.1 = f '(x) *(x - 1)

OpenStudy (bahrom7893):

I think your sign is off y - 0.1 = (1/25)(x-0.1) y - 0.1 = x/25 - 1/250

OpenStudy (bahrom7893):

y = x/25 - 1/250 + 1/10 = 0.04x + 0.096

OpenStudy (danjs):

you can always graph everything and check if they look right, https://www.desmos.com/calculator

OpenStudy (babynini):

Where did you get that big 250?!

OpenStudy (bahrom7893):

gah im wrong

OpenStudy (danjs):

x,y) = ( 1 , 0.1)

OpenStudy (danjs):

tangent - x/25 - 0.06

OpenStudy (bahrom7893):

y - 0.1 = (1/25)(x-0.1)**** y - 0.1 = x/25 - 0.04

OpenStudy (bahrom7893):

OMG

OpenStudy (danjs):

hah

OpenStudy (bahrom7893):

y - 0.1 = (1/25)(x-1)**** y - 0.1 = x/25 - 0.04

OpenStudy (babynini):

when you add 0.1 to 0.04 it equals 0.14 though..

OpenStudy (bahrom7893):

y = x/25 - 0.04 + 0.1

OpenStudy (bahrom7893):

so youre actually subtracting .04 from .1

OpenStudy (babynini):

ooh I see i see.

OpenStudy (babynini):

And then the normal is the same, except -1/(1/25)

OpenStudy (babynini):

Which comes out to..

OpenStudy (babynini):

-25x-0.06 ??

OpenStudy (danjs):

lol yeah -1/25 - 1/10 = 3/50 or about 0.06

OpenStudy (danjs):

plus 1/10 omg

OpenStudy (bahrom7893):

lol long day for everyone

OpenStudy (danjs):

lol yeah -1/25 + 1/10 = 3/50 or about 0.06

OpenStudy (babynini):

Oh my gosh, coffee break yall.

OpenStudy (babynini):

You guys are doing excellent! no worries!! We can do this! xD

OpenStudy (danjs):

screw the arithmatic, as long as you get the concepts

OpenStudy (babynini):

but I gotta turn this in ..hehe normal = -25x-0.06 ?

OpenStudy (bahrom7893):

three tired brains is better than 1 tired brain i suppose - at least we catch everyone else's mistakes

OpenStudy (danjs):

you find a function for the slope (derivative), calculus over

OpenStudy (danjs):

finish with algebra

OpenStudy (babynini):

asfpaig the thing says both answers are wrong :(

OpenStudy (danjs):

graph them and see what it looks like

OpenStudy (babynini):

OpenStudy (danjs):

for the normal, same point and inverse negative slope, m = -25, point (1, 0.1), calculate that line again

OpenStudy (danjs):

not sure maybe all decimals or all fractions wanted, syntax

OpenStudy (babynini):

oo maybe. so how do i do 0.06 in fraction=.=

OpenStudy (babynini):

35/250? haha

OpenStudy (danjs):

normal y - 0.1 = -25*(x - 1)

OpenStudy (danjs):

y = 25.1 - 25x

OpenStudy (babynini):

y = -25x+25.1

OpenStudy (babynini):

haha yeah. So for the tangent it would be?

OpenStudy (babynini):

tan : 0.04x-0.06

OpenStudy (babynini):

Nope, it didn't like that.

OpenStudy (babynini):

OpenStudy (danjs):

OpenStudy (babynini):

AHA I GOT IT

OpenStudy (babynini):

oh dude, we got it at the same time lol. idk why i had the 0.06 negative.

OpenStudy (anonymous):

...and nvm, I misread the problem xD

OpenStudy (babynini):

OpenStudy (babynini):

You guys are amazing <3 thanks for staying with me lol

OpenStudy (danjs):

yeah, dumb computer checking tools i guess you should choose decimal or fraction, and have to stay the same for everything

OpenStudy (danjs):

welcome, if you have another similar, i am sure it will be done in 2 or less responses, i promise

OpenStudy (babynini):

Right. Quick question though how come it had to be put in as 25.1-25x rather than -25x +25.1 ?

OpenStudy (babynini):

aw thank you:) i'm all done for today!! Though I should probably do some practice ones o.o clearly.

OpenStudy (danjs):

sorry was afk

OpenStudy (danjs):

i dont know, whoever programmed the thing did it

OpenStudy (danjs):

just always lead with a positive value if you can , i guess

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