Question

Who can help me solve these?? Attaching picture

Answer 1

This

Answer 2

\[1)x ^{2}+6x-11\]

Answer 3

2)\[-x^{2}-3\]

Answer 4

are u following

Answer 5

@dayakar yes

Answer 6

3)\[5x^{2}-33x+28\]

Answer 7

How did you get these answers? When I try to do it, I get weird numbers :/

Answer 8

HI !

Answer 9

you should not get numbers, you should get expressions with an \(x\) in them

Answer 10

\[3x-7+x^{2}+3x-4\]

Answer 11

for example \[3x-7-(x^2+3x-4)\] distribute the minus sign\[3x-7-x^2-3x+4\] then combine like terms to get \[-x^2-3\]

Answer 12

yes,it is

Answer 13

so confused >.<

Answer 14

which one

Answer 15

#3, how'd you get 5x^2-3x+28?? @dayakar

Answer 16

Also are they put in the correct way?

f(x) = 3x - 7
g(x) = x^2 + 3x - 4

1.Find (f + g)(x). (3x-7)+(x^2+3x-4)
2. Find (f - g)(x). (3x-7)-(x^2+3x-4)
3. Find (f · g)(x). (3x-7)*(x^2+3x-4)
4. Find (f/g)(x). (3x-7)/(x^2+3x-4)
5. Find (g/f)(x). (x^2+3x-4)/(3x-7)
6. Find (f ◦ g)(x). 3[x^2+3x-4]-7
7. Find (g ◦ f)(x). [3x-7]^2+3[3x-7]4 ????

i feel like #7 is written wrong?

@dayakar @misty1212

Answer 17

!)(f+g)(x)=f(x)+g(x)

Answer 18

\[=3x-7+x^{2}+3x-4\]

Answer 19

@dayakar I know how to set them up for the most part, but figuring oh I solve them is beyond confusing me :/

Answer 20

okay so i set up #1 right.

Answer 21

2)same way u do sutraction,can u do it

Answer 22

3x-7-x^2+3x-4 ?

Answer 23

no

Answer 24

wait.. what? :/

Answer 25

\[3x-7-x^{2}-3x+4\]

Answer 26

why +4?

Answer 27

multiply with - sign inside the bracket signs

Answer 28

get it

Answer 29

what happens are u following

Answer 30

@dayakar yes sorry i have a baby so it might take me a minute to respond....

Answer 31

ok,take ur own time

Answer 32

@dayakar Okay an yes i get it now

Answer 33

3)

Answer 34

3x-7*x^2+3x-4 ?

Answer 35

\[(3x-7)(x^{2}+3x+4)=3x(x^{2}+3x+4)-7(x^{2}+3x+4)\]

Answer 36

sorry ,i typed +4 instead of -4 change it

Answer 37

r u following

Answer 38

yes :)

Answer 39

can u simplify it

Answer 40

uhh.. i can try... :/ i'm not good at that lol

Answer 41

plz, try u can

Answer 42

ok give me a moment!

Answer 43

ok so for 3x(x^2+3x-4) i got 4x^3+9x-12

then for -7(x^2+3x-4) i got -7x^2-21x-28

lol.. >.<

Answer 44

\[3x^{3}+9x^{2}-12x-7x^{2}-21x+28\]

Answer 45

compare where u did wrong

Answer 46

okay i added a number to the 3x^3, i didn't add the exponent to the 9, and i didn't add the x to 12. and i didn't +28 i -28.

Answer 47

it is not adding , it is multiplying

Answer 48

can u simplify

Answer 49

yeah i know i thought thats what i was supposed to do :/

Answer 50

yeah let me try

Answer 51

i got 3x^3-16x^2-9x+28?

Answer 52

but you said earlier it was 5x^2-3x+28 so what did i do wrong?

Answer 53

\[3x^{3}+2x^{2}-33x+28\]

Answer 54

wait how??

Answer 55

that was a mistake

Answer 56

so my final answer is 3x^3+2x^2-33x+28?

Answer 57

yes

Answer 58

ok take it one step at a time ok

Answer 59

@dayakar @samthamathguy okay so how would i do 4 and 5?

Answer 60

4)

Answer 61

factorise the denominator first

Answer 62

ok so if you think x is a number - or divideing by another number

Answer 63

\[x^{2}+3x-4\]

Answer 64

so what do you think the x means

Answer 65

i think i know

Answer 66

@dayakar @samthamathguy give me one sec to reply :)

Answer 67

\[x^{2}-x+4x-4\]
spliting the middle term

Answer 68

ok so what i think it is is something plus 4 to get 7

Answer 69

so its probaly 1 and 1 half

Answer 70

are we on 4 ? lol

Answer 71

yay

Answer 72

so am i right on x = 1 and 1/2