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Mathematics 15 Online
OpenStudy (iwanttogotostanford):

PLEASEE HELP: Which

OpenStudy (iwanttogotostanford):

@zepdrix @Nnesha @Vocaloid

OpenStudy (iwanttogotostanford):

@MathleticMagician @math&ing001 @zpupster

OpenStudy (iwanttogotostanford):

@imqwerty i think its the first one?

imqwerty (imqwerty):

yea correct (:

OpenStudy (iwanttogotostanford):

@imqwerty Thanks could you help me with a couple more please

imqwerty (imqwerty):

yea sure (:

OpenStudy (iwanttogotostanford):

@imqwerty

imqwerty (imqwerty):

the polynomial in x with roots say α,β,γ can be given by- f(x)=(x-α)(x-β)(x-γ) (: try to do it now

OpenStudy (iwanttogotostanford):

I think its B but Im not sure

OpenStudy (iwanttogotostanford):

please help

OpenStudy (iwanttogotostanford):

@imqwerty

imqwerty (imqwerty):

putting 4,5,-7 in place of α,β,γ in f(x)=(x-α)(x-β)(x-γ) and simplifying we get- f(x)=(x-4)(x-5)(x-(-7)) did u do this?

OpenStudy (iwanttogotostanford):

yes thanks and I sent you a message!

OpenStudy (iwanttogotostanford):

@imqwerty

imqwerty (imqwerty):

i didn't get ur pm :/ this ws the problem with many os users wait a sec ima send to a pm then u tell if u recieved it or not

OpenStudy (iwanttogotostanford):

ok

imqwerty (imqwerty):

i sent the message did u get it?

OpenStudy (iwanttogotostanford):

no

OpenStudy (mathmate):

Hints: Use the property of multinomials: \((x-a)(x-b)(x-c)=x^3-(a+b+c)x^2+(ab+bc+ca)x+abc\) So if a,b,c are the roots, the constant term =abc, the second coefficient=-(a+b+c).

imqwerty (imqwerty):

the message thing is working ):

OpenStudy (iwanttogotostanford):

ok well basically I said I just need the answer lol I have a ton to do and this is taking a while thats what i was saying...

imqwerty (imqwerty):

XD

OpenStudy (iwanttogotostanford):

sorry!

imqwerty (imqwerty):

A

OpenStudy (iwanttogotostanford):

is it actually?

imqwerty (imqwerty):

its ok i can feel ur pain but hey i'll not answer only a few cause its not good and yes A is correct

OpenStudy (iwanttogotostanford):

ok i understand thanks one more though?? I have to do the rest on my own anyway

imqwerty (imqwerty):

ok (: only 1 more

OpenStudy (iwanttogotostanford):

Which of the following is a polynomial with roots 5, 4i, and −4i? f(x) = x^3 − 5x^2 + 20x − 16 f(x) = x^3 − 5x^2 + 16x − 80 f(x) = x^3 − 20x^2 + 5x − 16 f(x) = x^3 − 16x^2 + 80x − 5

OpenStudy (mathmate):

@iwanttogotostanford It's taking time because you are not learning to solve the the problem. If you learned how to solve these problems, each one can be solved in 10 seconds. Read my post and you'll see.

OpenStudy (iwanttogotostanford):

thank you so much!

imqwerty (imqwerty):

@mathmate is correct :D

OpenStudy (iwanttogotostanford):

@mathmate I know how to do the problems i don't have time to right now and I have to do a lot more!

OpenStudy (mathmate):

This one you can solve in less than 5 seconds! lol

imqwerty (imqwerty):

and u shuld learn @mathmate 's trick u can solve such prblms in seconds with it (:

OpenStudy (iwanttogotostanford):

ok whats the trick?n Id love to know

OpenStudy (mathmate):

Hints: Use the property of multinomials: (x−a)(x−b)(x−c)=x3−(a+b+c)x2+(ab+bc+ca)x+abc So if a,b,c are the roots, the constant term =-abc, the second coefficient=-(a+b+c). Take the previous example: THanks!: Which of the following is a polynomial with roots 4, −5, and 7? f(x) = x^3 − 6x^2 − 27x + 140 f(x) = x^3 − 6x^2 − 20x + 27 f(x) = x^3 − 20x^2 − 27x + 35 f(x) = x^3 − 20x^2 − 35x + 140 4*(-5)*7 = \(\color{red}{-140}\) So the answer can be: f(x) = x^3 − 6x^2 − 27x + 140 or f(x) = x^3 − 20x^2 − 35x + 140 4+(-5)+7 =\(\color{red}{6}\) So the answer has to be \(f(x) = x^3 \color{red}{− 6}x^2 − 27x + \color{red}{140} \)

OpenStudy (iwanttogotostanford):

@imqwerty could you please tell me what the last one is really quick thats all

OpenStudy (iwanttogotostanford):

@zepdrix

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