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Find dy/dx for tan(x+y)=y.
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@oldrin.bataku CAN U HELP?
you might indicate what you expect in terms of a steer. you can just do it implicitly. ie \( \dfrac{d}{dx} tan(x+y) = \dfrac{d}{dx} y\) bearing in ming [presumably] that \(y = y(x)\) or you can make a substitution so you are not looking at a mixed argument, eg let \(u = x + y, \qquad u' = 1 + y'\) or maybe you're happy looking at partials so \(f(x,y) = tan(x+y)-y\) and \(\dfrac{dy}{dx} = -\dfrac{f_x}{f_y}\) which can make things easy.
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