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please help solve using substitution x-4y=-5 12y=15+3x
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you can solve the first equation for \(x\) via \[x=4y-5\] then substitute in to the second one and get \[12y=15+3(4y-5)\] and solve that for \(y\\)
i tried but i don't think i got it right
what did you get ? please show ur work so we can find ou tthe mistakes :=))
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