Question

I need help with Geometric Series
1+2+4+8 + ... a10

Answer 1

we can apply this formula:
\[{a_{10}} = {a_1}{q^9}\]
being \(a_1\) the first term, namely \(a_1=1\) and \(q= a_3/a_2=2\). \(q\) is the constant of your geometrical series
So, substituting, we have:
\[{a_{10}} = {a_1}{q^9} = 1 \cdot {2^9} = ...?\]

Answer 2

=512