Question

Triangle ABC is translated on the coordinate plane below to create triangle A'B'C':

Triangle ABC, triangle A prime B prime C prime, and parallelogram EFGH on the coordinate plane with ordered pairs at A negative 7, 6, at B negative 5, 3, at C negative 1, 3, at A prime 1, 4, at B prime 3, 1, at C prime 7, 1, at E negative 5, negative 2, at F negative 1, negative 2, at G negative 3, negative 5, at H negative 7, negative 5

If parallelogram EFGH is translated according to the same rule that translated triangle ABC, what is the ordered pair of point H'?

Answer 1

@Ghostgate

Answer 2

(−15, −3)
(−9, 3)
(1, −7)
(−5, −13)



Those are my options. im not sure what to do

Answer 3

I will help one min

Answer 4

Any idea how to start?

Answer 5

Is there a picture that comes with this problem?

Answer 6

First you need to find the rule or 'equation' that this system goes by before we can solve what H' point is located. So, to do so, label out the triangles points:
A(-7, 6), B(-5, 3), C(-1, 3) to A'(1, 4), B'(3, 1), C'(7, 1)
Now for A to A' which is -7 to 1 is a 8 point difference and A to A' which is 6 to 4 is a -2 point difference, indicating:
(x + 8, y - 2) - Now:
B(-5, 3) -> (-5 + 8, 3 - 2) = B'(3, 1)
C(-1, 3) -> (-1 + 8, 3 - 2) = C'(7, 1)
Now to simply solve for H to H':
We know H 's coordinates are: (-7, -5)
Now add in the rule and solve:
(-7 + 8, -5 - 2) = What?
I will allow you to solve this yourself.
I hope this helps you!
{---Ghostgate---}

Answer 7

1, -7?

Answer 8

Let me solve one second

Answer 9

I have gone through your problem here, it looks like you did a great job finding the rule for the translations, in that (x+8,y-2)

Answer 10

@lolbug Yes, I would believe that H' is (1, -7).
@jchick Are you trying to check my answers? I mean, I don't mind, but I'm pretty sure it all comes out correctly.

Answer 11

Yes 1, -7 is correct

Answer 12

No I was simply looking it over and solving as well

Answer 13

As well as saying good job in the process

Answer 14

1, -7 is correct