Question

Find the perimeter of the following shape, rounded to the nearest tenth:

Shape ABCD is shown. Point A is at 5, 5. Point B is at 7, 3. Point C is at 3, 0. Point D is at 1, 2.

12.5
15.7
16
16.5

Answer 1

Using the distance formula:
\[\sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y_{1})^{2}}\]

You can calculate the length of the long side and the length of the short side/width. Since it's a rectangle, the perimeter would simply be: \[2(l+w)\]

Answer 2

Using the distance formula, figure out distance between C and D for w (or the width). And figure out the distance between C and B for l (or the length).

Then add them together and multiply by two for your perimeter.

Answer 3

so do i put each point into the distance formula?

Answer 4

is it 16?

Answer 5

I'm assuming you have to round at the very end? Don't round before you get to the end or you might get a different number.

Answer 6

so its not 16?

Answer 7

its the last question to my homework but i cant get it

Answer 8

When I'm rounding at the end, I'm getting a number close to 16 and it's on your list of answer choices.

I think everything you're doing is right, but you just have to enter everything in and round at the very end.

Answer 9

ill show you what i did real quick and you tell me if im doing something wrong :)

Answer 10

Ok :)