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Algebra 17 Online
OpenStudy (zasharra):

please help me with an assignment!!!

OpenStudy (zasharra):

Create an equation that results in at least one extraneous solution. Work through your equation, justify each step, and explain how the solution is extraneous.

OpenStudy (zasharra):

Using the properties of exponents and radicals, design at least three different equivalent forms of x². You must show how each one can be simplified back to x² in two or more steps. Stretch your mind and get creative! Keep in mind that something too simple, like x • x would not be acceptable since it takes only one step to convert it to x².

OpenStudy (zasharra):

Substitute your birthday into the equation Square root of the quantity x minus y + m = d, where y is the last two digits of your birth year, m is the month, and d is the day. If you were born on 7/10/1856 like Nikola Tesla, your equation would be Square root of the quantity x minus 56 + 7 = 10. Solve for x and identify if it is an extraneous solution.

pooja195 (pooja195):

@TheSmartOne

pooja195 (pooja195):

I dont know this :c

pooja195 (pooja195):

@jagr2713 @Data_LG2 @amistre64

pooja195 (pooja195):

@Nnesha @Jaynator495

pooja195 (pooja195):

@Luigi0210

pooja195 (pooja195):

@mathstudent55

OpenStudy (amistre64):

this is 3 different questions, and i do not take well to 'deadlines'

OpenStudy (amistre64):

what have you considered for the first one?

OpenStudy (zasharra):

It's one whole assignment

OpenStudy (zasharra):

I don't know this at all.. I AM WILLING TO WORK

OpenStudy (amistre64):

i do not have the time required to work thru it at the moment. srry.

OpenStudy (zasharra):

Can anyone one HELP ME PLEASSSSEEEEEEE!!!!!!!!!!

OpenStudy (zasharra):

@Deadly_Roses @Luigi0210

OpenStudy (zasharra):

@Data_LG2

OpenStudy (anonymous):

For the first one, do you know what an extraneous solution is? It is something (can be roots or simplified form of the eqn) that cannot satisfy the original equation. I'll give you an example and you must gave me another example. let's say for a rational function we have: \(\sf \Large f(x)=\frac{(x+2)}{(x^2-4)}\) try finding the zeros of this function, to do that you'll have to simplify it: \(\sf \Large f(x)=\frac{(x+2)}{(x+2)(x-2)}\) you'll see that x must not equal to x=2 o r x=-2 but the zero of the numerator is x=-2, which means that x=-2 is the extraneous solution because it is one of the restriction in the domain of the function. (I'm not sure if the way your teacher had taught you, so I'm just following what I know).

OpenStudy (zasharra):

srry im reading it now. i was in another window

OpenStudy (anonymous):

For 2nd one, maybe you can tell us what have you learned in class. Like what are the examples that your teacher is giving you in the class, so that we will have a basic idea on how we are going to help you.

OpenStudy (anonymous):

For the 3rd one, I expect that you already attempted this one because it requires your birthday. Try following the instructions on the question, carefully and try substituting the values. If you ever got stuck, don't hesitate to ask :)

OpenStudy (zasharra):

An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.

OpenStudy (anonymous):

yeah okay. So did you understand the example I gave above?

OpenStudy (zasharra):

could this be the final answer or am i wrong?

OpenStudy (zasharra):

I really dont know what they're asking for

OpenStudy (anonymous):

@jim_thompson5910 @satellite73 @ganeshie8 @nincompoop

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