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Mathematics 8 Online
OpenStudy (watermelon14):

question

OpenStudy (watermelon14):

\[x=2+\sqrt{3x-8}\]

OpenStudy (watermelon14):

the question asks what the smallest solution interval is and the answer is (2,4)

OpenStudy (watermelon14):

but idk how to do it

OpenStudy (watermelon14):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

first move the 2 over (subtract 2 from both sides)

jimthompson5910 (jim_thompson5910):

then square both sides. You'll have to use the FOIL rule or the box method

OpenStudy (watermelon14):

yep i did that and i got x=4 x=3

jimthompson5910 (jim_thompson5910):

so the interval they give you is (2,4) ?

OpenStudy (watermelon14):

it is multiple choice A)(-2,0) B)(0,2) C)(2,4) D)(4,6)

OpenStudy (watermelon14):

it asks The smallest solution of (the equation) lies in the interval:

jimthompson5910 (jim_thompson5910):

ah I see now

jimthompson5910 (jim_thompson5910):

you got x = 3 or x = 4. Those are the correct solutions to the original equation x = 3 is the smaller of the two solutions The question is: which of the intervals listed has x = 3 in it?

jimthompson5910 (jim_thompson5910):

example: A)(-2,0) is NOT the answer because 3 is NOT in the interval from -2 to 0 excluding the endpoints

OpenStudy (watermelon14):

ohhh i see i know that (2,4) is the correct answer but, if an answer choice was (2,3) would that also not be right because it doesn't have 4?

jimthompson5910 (jim_thompson5910):

it wouldn't be correct because while 3 is the endpoint, the endpoint is not included

OpenStudy (watermelon14):

k got it thank you!!

jimthompson5910 (jim_thompson5910):

you're welcome

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