question
\[x=2+\sqrt{3x-8}\]
the question asks what the smallest solution interval is and the answer is (2,4)
but idk how to do it
@jim_thompson5910
first move the 2 over (subtract 2 from both sides)
then square both sides. You'll have to use the FOIL rule or the box method
yep i did that and i got x=4 x=3
so the interval they give you is (2,4) ?
it is multiple choice A)(-2,0) B)(0,2) C)(2,4) D)(4,6)
it asks The smallest solution of (the equation) lies in the interval:
ah I see now
you got x = 3 or x = 4. Those are the correct solutions to the original equation x = 3 is the smaller of the two solutions The question is: which of the intervals listed has x = 3 in it?
example: A)(-2,0) is NOT the answer because 3 is NOT in the interval from -2 to 0 excluding the endpoints
ohhh i see i know that (2,4) is the correct answer but, if an answer choice was (2,3) would that also not be right because it doesn't have 4?
it wouldn't be correct because while 3 is the endpoint, the endpoint is not included
k got it thank you!!
you're welcome
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