Question

Look at the figure shown below. CB is a segment on which a perpendicular bisector AD is drawn. D is the midpoint of CB.

Which step should be used to prove that point A is equidistant from points C and B?

Answer 1

Triangle ABD is congruent to triangle ACD.

Prove that segment AD is perpendicular to BC.

Triangle ABD is similar to triangle ACD.

Prove that segment AD is equal to segment BC.

Answer 2

I think its A because of the ASA theorem, but im not sure if im right :/

Answer 3

@Nnesha @Loser66 @phi

Answer 4

@Shadowknight6263

Answer 5

you are right :)

Answer 6

thank you very much! :)

Answer 7

just to clarify: if the two traingles are congruent then AC=AB ....in other words, A is equidistant from B and C

Answer 8

yes! A would be the mid-point right? equal distance from B and C